Recent content by amazondog

Should it be v1 = 5.05e5 + 16v2? (v1^2) = (v1x)^2 + (v1y)^2 (v1^2) = { (383022.2216 - (4)(v2) }^2 + ( 321393.8048)^2 (v1^2) = (1.4671e11 - 16v2^2 + 1.0329e11) (v1^2) = 2.50e11 - 16v2^2 (v1) = 5.0e5 - 4v2)

"neutron collides elastically with a helium nucleus" Homework Statement A neutron collides elastically with a helium nucleus (at rest initially) whose mass is four times that of the neutron. The helium nucleus is observed to rebound at an angle θ'2 = 40° from the neutron's initial...

So the x and y components are both 30.4. That would be the x component cancels (30.4-30.4) but the y component would double because its going upwards..?

same speed, different velocity. But because the angles, speeds, and masses are the same don't they cancel?

Is there change in momentum though? Cause its going the same velocity.

Homework Statement A tennis ball of mass m = 0.087 kg and speed v = 43 m/s strikes a wall at a 45° angle and rebounds with the same speed at 45° (Fig. 7-29). What is the impulse given the wall? Homework Equations Impulse = M x V Sin (theta) = opp/hyp The Attempt at a Solution...

cos!

I think i GOT the force required to go up the mountain. Can someone please verify? Fa - Ff - F// = 0 Fa - umgsin(theta) - mgsin(theta) = 0 Solve for Fa.

For the force required to go up the hill is it Fa - Ff = FN Facos(theta) - umgcos(theta) = mgsin(theta)

Ok, so the coefficient of velocity is tangent to the path. That makes sense.

umg = mgsin(theta ?

Ok, the question as written is: Question: A bicyclist is traveling down a hill which has a 9.75 degree incline at a constant velocity of 5.95m/s. The mass of the cyclist and bike combined is 98.7kilograms. - What is the coefficient of friction of the surface the biker is traveling on...

Sorry, my bad I re-wrote the question without it in front of me. It is going Down and it asks for the rest when it goes up. But how do i find the coefficient?

Nasu, no i am not given an Fa. All I have is: A biker rides up an 9.75degree hill at a constant speed of 5.95m/s. The biker and bicycle together have a mass of 98.7kg. Find the coefficient.. What force does the system need to make the biker go up the hill at the same velocity.. What must...

umgcos(theta) - gcos(theta) = 0 That would be a very small number...