Recent content by Amel

Yeah I got it. mgh is PE and .5mv^2 is KE at the top then you have .5mv^2 at the bottom and find the difference. got 3.72e+01 J. and it was right.

Ok thanks I got it right.

So do you do (1/2)mv^2 for both speeds? and find the difference? or do you use mgh= PE

Ok so the rpoblem is A 2.20kg box slides down a rough incline plane from a height h of 1.63m. The box had a speed of 2.33m/s at the top and a speed of 1.90m/s at the bottom. Calculate the mechanical energy lost due to friction (as heat, etc.). and I am not sure where to even begin with this...

Homework Statement A mass M is initially at rest on a horizontal surface, mus=0.30 and muk=0.20 . A horizontal string then pulls M with a tension T. Forces below are magnitudes A) N equals Mg B) If M does not accelerate, then T less than or equal mu_s N C) M will accelerate if T exceed...

cool I got it right it was 1i+23j+9k square the coeficents add them up and then square root to find the force N.

Homework Statement The location of a particle (in m) is given by its x, y and z coordinates as function of the time (in s) as: x = -33+29t and y = -11-27t+7t2 and z = 95-9t-5t2 What the magnitude of the object's acceleration at t = -10.00s? The Attempt at a Solution Ok so I am...

so i+23j+3k ? what units do I use for this? its saying I am not using the right units. Isn't it N*m/s^2

Homework Statement Two forces F1 and F2 are acting on a mass M=4kg. The force F1 = 11i + 5j + 7k, in N. The acceleration of the mass is given by a = 3i + 7j + 4k, in m/s2. Calculate the magnitude of F2 . Homework Equations F = ma The Attempt at a Solution Ok so what I tried here...

Homework Statement A small steel ball bearing with a mass of 29.0 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.41 m. Calculate the horizontal distance the ball would travel if the same spring were aimed 29.0o...

Thanks for that hint I got it.

Homework Statement A) If a non-zero net force acts on an object, the object's velocity will change. B) If a non-zero net force acts on an object, the object's speed will change. C) A bicycle initially moving at a constant velocity will slow down unless a small net force is applied. D)...

I was getting it wrong because I was putting kN instead of N. I missed that the book converted their answer to kN, Thanks I needed to see N = kg*m/s^2 to catch my mistake.

It just says 19.221 kN is wrong it doesen't tell me anything else. Are my units right? I don't get why I am getting this wrong.

I know gravity is downwards but there is a problem in the book just like this and this is how they get to that equation. T + Fg = ma so since Fg is negative T - mg =ma T = ma+mg T = m(a+g) I know that gravity was negative but that's why they added mg over to the other side.