Recent content by Ameya Darshan

i understood the second case thanks to kuruman but I'm still not able to work out the first case.

the fact that I'm not able to explain how i got it certainly tells me i was wrong. :-/

I get T = 10(g-a) = kx. is that right? but this has 'a' in it's equation, so how would i compare it to the second case?

l don't understand, could you please explain further?

okay, so the extension will be kx=mg so x =mg/k. am i right? and was the equation for my first case right?

5g in both.

wouldn't a be 0 if we assume no spring?

i use the equation 5(g+a)-kx = 5(g-a) to get a = kx/10.

how can i? i mean, it's related to k and extension in the spring. sorry if I'm missing something very common.

this is the second case.

my bad I'm so sorry. the spring is connected to the block.

Homework Statement Scenario: a block of mass 5 kg is hanging from a spring from an ideal pulley from one side, the other side supporting a mass of 10 kg through a STRING. Now, the 10 kg block replaced with a 5 kg block. In which case would the extension in spring be greater, assuming constant...

I got the right answer! Thanks! And thank you for the welcome. :-)

but the system is initially at rest, no? so wouldn't velocity will be imparted to the cart only after the man has jumped?

This is what I did. Conserving momentum: mv=2m(x) therefore x = velocity of cart = v/2 Apply work energy theorem: W = mv^2 + (2m)(v^2/4)/2 = 3mv^2/4