Recent content by amilapsn

Plug in some values, Draw some examples, Although it can't be done, Try to get some counter examples.. And ah ha! In a moment or two, You'll get the intuition!

Thank you!

Does SNR give a clue to bandwidth limitations? i. e. Would it help to figure out how the signal is distorted due to the limitation of the bandwidth? I think answer is "no" though.

Me too...

universal generalization:if P(a) is true for all a in universe of discourse then we can say $$\forall x P(x)$$

what is the value of R in ohms?

Somebody tell me whether I'm right or wrong...

I didn't get you... Do you mean this...? ##Assume\ \forall x\forall y\ p(x,y)## ##Let\ y_0\in \mathbb{R}## ##\ \ \therefore \ \forall x \ p(x,y_{0})## ##\ \ Let\ x_0\in \mathbb{R}## ##\ \ \ \ \therefore\ p(x_0,y_0)## ##\ \ \therefore \forall x\ p(x,y_0)##...

Homework Statement This question may seem as an axiom to some. I also feel the same. Prove: ##\forall x\forall y\ p(x,y)\Leftrightarrow\forall y\forall x\ p(x,y)##The Attempt at a Solution [/B] ##Assume\ \forall x\forall y\ p(x,y)## ##Let\ x_0\in \mathbb{R}## ##\ \ \therefore \...

Just now I felt what is called as "Enlightenment..."

Yeah, it's really clearer...

Then the proposition is true for all a, so that we can't disprove it. We have to prove it. Thanks again @PeroK

I see. The proposition holds for a=1 too, because A(1) false and B(1) false. Thanks... Thank you for showing me the better way to look at the question.:smile:

Because a=1 is not less than for all ##\epsilon>0##

The proposition holds for a=-1,0. But it doesn't hold for a=1.