Recent content by Analog711

I apologize if this seems much too "freshman", and may come across as annoyingly simple to some more trained or educated on this board. However I will ask the question anyways as I have failed to find an answer elsewhere. Under Newton's Second Law of Motion, f=ma. thus F = kg (m/s^2)...

Borek, correct, I have since reworked my calculations. a) 62.1g/mol b) 1.21g H2O * (1 mol H2O / 18.016 g H2O) * (2 mol H/ 1 mol H2O) = .134 mol H 1.39g [compound] * (1 mol [compound] / 62.1 g) = .0224 mol [compound] .134 mol H/ .0224 mol [compound] = 5.98 , approx. 6 thus 6 hdron...

(62.1g/mol / 1.39g [binary gaseous compound] ) = 44.6 mol binary gaseous compound 1.21g H2O * (1.008g/18.016g) * (1 mol H/ 1.008g H) = 0.0672 mol H

I used the "1.94 times" information given from the problem to find the molecular mass of the compound after finding the vapor density formula on wikipedia. (32g/mol O2/2.016g/mol H2) = 15.873 15.873*1.94 = 30.8 . 30.8 *2.016 = 62.1 g/mol (molar mass of the gaseous binary compound) So I have...

Homework Statement "A gaseous binary compound has a vapor density that is 1.94 times that of oxygen at the same temperature and pressure. When 1.39g of the gas is burned in an excess of oxygen, 1.21 g water is formed, removing all the hydrogen originally present. (a) Estimate the molecular...