Recent content by andrewdavis23

When I was checking my work, Wolframalpha took my trig work a step further with an identity that no one in my Calculus II class has ever seen, including my teacher. csc(2x) - cot(2x) = tan(x) I tried to prove the identity myself and I looked online, but no luck. Please, could someone...

Homework Statement An isolated capacitor C1 carries a charge Q0. Its wires are then connected to those of a second capacitor C2, previously uncharged. What charge will each carry now? What will be the potential difference across each? Homework Equations C=Q/VThe Attempt at a Solution I figured...

I think I see what was throwing me off. We wrote down m2=15g and m1=10g, but we also had a base weight on each piece of 55g (to "slow down the system"). So when I go to put it in the equation for acceleration [ a=((m2-m1)g)/(m2+m1) ] I need to make m2=(15g+55g) and m1=(10g+55g) because while the...

I tried the correct equation and got 0.8m/s^2 for a (inputing g=9.8m/s^2). This has to be right then...so thank you very much for the help!

I actually tried again, figuring m2a2=m2g-m1g, plugged in the numbers 60g*a2=60g * 9.8m/s^2 -55g * 9.8m/s^2. I solved for a2 and got 0.8m/s^2, does that seem right? If its not I originally used the equation g = a (m1+m2) / (m2-m1) and solved for acceleration and got 9.8m/s^2 and I'm sure that...

Homework Statement The descending mass of the pulley system (atwood machine) is 60g and the ascending mass is 55g. Using DataStudio to measured the slope of the velocity over time (read by the spinning spokes of the pulley) the acceleration (constant) is experimentally given as 0.316m/s^2...