Recent content by andyfeynman
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What Is the Minimum Velocity Required for a Sphere to Overcome a Step?
Homework Statement A uniform solid sphere of radius R rolls without slipping at velocity V on a level surface. It collides with a step of height h. Assume that after the collision, the sphere maintains contact with the step at point A with no slipping. Find the minimum value of V for the...- andyfeynman
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- Ball Rolling
- Replies: 8
- Forum: Introductory Physics Homework Help
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Centripetal Force Experiment: Impact of Free Mass on Error
Homework Statement I'm doing the lab report questions for the centripetal force experiment using this apparatus: ftp://ftp.pasco.com/Support/Documents/english/ME/ME-8088/012-08478B.pdf. One of the lab questions asks whether using a larger "free mass" reduces the percentage error. Homework...- andyfeynman
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- Centripetal Centripetal force Experiment Force
- Replies: 1
- Forum: Introductory Physics Homework Help
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Convergence and Cauchy Criterion
Homework Statement Suppose the sequence (xn) satisfies |xn + 1 - xn| < 1/n2, prove that (xn) is convergent. Homework Equations |xn - xm| < ɛ The Attempt at a Solution If m > n, then |xn - xm| < |xn - xn + 1| + |xn + 1 - xn + 2| + ... + |xm - 1 - xm| < 1/n2 + 1/(n+1)2 + ... + 1/(m - 1)2 <...- andyfeynman
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- Cauchy Convergence
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Proving Convergence of a Sequence Using Cauchy Criterion
Just forgot it. I made a very stupid mistake. But I came up with the idea of letting bk = 21/k - 1. This means bk2 < 4[k(k-1)] for all k > 2. Therefore, xn = 1 + b22 + ... + bn2 < 1 + 4/[1(2-1)] + ... 4/[n(n-1)] = 1 + 4(1 - 1/2) + ... + 4[1/(n-1) - 1/n] = 5 - 4/n < 5 Since xn is monotone...- andyfeynman
- Post #3
- Forum: Calculus and Beyond Homework Help
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Proving Convergence of a Sequence Using Cauchy Criterion
Homework Statement Show that the sequence {xn}: xn := (21/1 - 1)2 + (21/2 - 1)2 + ... + (21/n - 1)2 is convergent. Homework EquationsThe Attempt at a Solution If n > m, |xn - xm| = (21/n - 1)2 + (21/(n-1) - 1)2 + ... + (21/(m+1) - 1)2 < (21/n)2 + (21/(n-1))2 + ... + (21/(m+1))2 < (21/(m+1))2 +...- andyfeynman
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- Convergence Sequence
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Three-pulley system and coefficients of friction
Thank you so much :smile:- andyfeynman
- Post #8
- Forum: Introductory Physics Homework Help
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Three-pulley system and coefficients of friction
Yes, I forgot that anything moving should be subject to kinetic friction, not static. So it should be m accelerates while 3m stays at rest?- andyfeynman
- Post #6
- Forum: Introductory Physics Homework Help
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Three-pulley system and coefficients of friction
This is what I thought: If the tension is larger than the maximum static friction of m but not of 3m, then only m would accelerate but 3m would stay unaccelerated.- andyfeynman
- Post #4
- Forum: Introductory Physics Homework Help
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Three-pulley system and coefficients of friction
Wow! I just notice how similar this problem is to Kleppner & Kolenkow 2.15. At least now I can be sure T is indeed 6/7(μk + 1)mg for case (2).- andyfeynman
- Post #2
- Forum: Introductory Physics Homework Help
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Three-pulley system and coefficients of friction
Homework Statement In the machine shown in the attached picture, all pulleys have negligible mass and rotational inertia. The coefficient of static friction μs between the table and either mass is larger than the coefficient of kinetic friction μk. The two masses 3m and m originally were held...- andyfeynman
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- Coefficients Friction System
- Replies: 7
- Forum: Introductory Physics Homework Help