Recent content by Angeee

Thank you-I like the link you sent. Looks like I need to still take the square root of the 6.3 which makes the correct answer...2.51m/s.

Ok so far i have work done by friction -36.75 which the cos 180 just gives me the negative. and the speed of small m=6.1 m/s using the eq-----mk*mgd=mgh2+1/2mv^2-mgh1 am I on the right track? I feel like i have missed some steps?

Homework Statement work done by friction=? as big M slides through a distance of 3 meters. what is the speed of small m when it hits the ground? M=5kg m=2kg m is 3meters above ground muk is.25 I can't figure out how to post a drawing (first post)Big M is horizonatal and frictionless b4...