y = -x then is the line that is tangent to the original curve 2y^3 + (6x^2)y - 12x^2 + 6y = 1. -1 also equals that tangent, the derivative you obtained. The two equations - the derivative and the original curve - should have a common point, which is the point P you are looking for.
jaaa 1st post! god please hlep me just becuase it is
we have this weird experiment given to us and its about how if u get a water flowing down a tube and make it slide down and hit a surface and make it flow hard/fast enuff the water makes a shape of a circle with some radius. we're supposed...