Recent content by anightlikethis

Here is the image I hope... http://www.webassign.net/giancoli/7-44fig.gif I found that velocity by solving the momentum conservation equation mav=mav1 + mbv2 for v2 and plugging into the kinetic energy conservation equation 1/2mav^2=1/2mav1^2+1/2mbv2^2 This became a quadratic equation...

"Simple" part of a hard problem involving momentum/kinetic energy conservation Two balls, of masses mA = 36 g and mB = 64 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60° angle with the vertical and released. (a) What is the velocity of the lighter ball before...

Homework Statement A 0.180 kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with half the original speed of the first ball.(a) What is the mass of the second ball?(b) What fraction of the original kinetic energy (KE/KE) gets...

Thanks, that was very helpful

Amtrak's high speed train, the Acela, utilizes tilt of the cars when negotiating curves. The angle of tilt is adjusted so that the main force exerted on the passengers, to provide the centripetal acceleration, is the normal force. The passengers experience less friction force against the seat...

OOPS ...sorrry here it is A car at the Indianapolis-500 accelerates uniformly from the pit area, going from rest to 300 km/h in a semicircular arc with a radius of 200 m. Determine the tangential acceleration of the car when it is halfway through the turn, assuming constant tangential...

Homework Statement [/b] A car at the Indianapolis-500 accelerates uniformly from the pit area, going from rest to I can't get very far on this one. I know that tangential acceleration= change in velocity over change in time, but there is no time mentioned. I know it has something to do...

Gosh I am sorry. I am really bad at this. I have the force that is due to gravity and against the car, but how can I get the steepness from that?

Yes okay Well this is all I've got: I drew a free body diagram and I think that there would be a car accelerating the car up the ramp of 1.43 N(because that is 20/14)*1060kg=1514.21 and gravity pushing it down in a line perpendicular to the ramp at 1060*9.8=10385. I assume I should fsomehow...

1. The problem: A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be so that even low-powered cars can get up the hills without slowing down. It is given that a particular small car, with a mass of 1060 kg, can...