It seems you are right, as by looking at the figure in my textbook I got the feeling that protons moved from body A through body B. I am attaching the exact same figure.
After reading your answer, now my thinking is +ve charge accumulation in B is because of replusion from body A, and there is...
What would happen if two metallic bodies (A and B) are touching each other, and a positively charged body C is brought closer to Body A.
C A<->B
I read in textbook that protons (positive charge) move from both A&B to extreme right of B, and all electrons from both A&B accumulate near C. So...
Please see the attached image. Here what would happen to positive charge and why ? Positive charge would move to ground or electrons would move from ground to Body B ?
Suppose , there is a body B1(-vely charged) and body B2(+vely charged). When both are on contact, electrons move from B1 to B2 as B2 is having electron deficit. But is reverse also possible that protons move from B2 to B1 as B1 is having proton deficit.
Decompose the problem, then try to add complexity one by one.
Initial decomposition reveals the problem given as attachment.
How current problem differs from attachment ?
For pulley, taking upward as ##+Y\uparrow##
##F \hat j + T(-\hat j) + T(-\hat j) = m_{pulley} . \vec{a_{pulley}} =...
Total PE gets dissipated by total frictional force (along incline + along horizontal path) and KE becomes zero at rest.
So, PE = Wfr1 + Wfr2, solve for Dhorizontal.
Find the permissible values for the "Maximum Horizontal Range of the projectile".
Use the formula for "Maximum Horizontal Range of the projectile" and solve it for Θ.
A falling apple made Newton to think about gravity. What made Einstien to think and develop his theory of relativity ?
What devices/apparatus/equipment did he use for his theory of relativity ?
Velocity will be V = 10*0.01 = 0.1ms-1.
Now, this velocity will be come initial velocity for motion A to B.
And since surface is frictionless, so
Vb = Ua = 0.1ms-1.
And as velocity will be constant from A to B, so t = AB/Ua = 10m/0.1ms-1 = 100sec.