Recent content by AnnaSuxCalc

PLEASE HELP I've been stuck on this question for DAYS!

Homework Statement Particle A moves along the line y = 29 m with a constant velocity of magnitude 2.8 m/s and directed parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with zero initial speed and constant acceleration of magnitude 0.42 m/s2...

o wow that sucks...a lot i just checked, i typed everything right...no mistakes :(

lmao Okay, MrUnknown who is either Justin or someone who knows Justin...that would be alittle late don't you think?...why don't you tell me the right answer then?

I did well in my high school calculus and the calculus I am taking now is supposed to be an introduction, it is the only calculus I have to take so I just need to get through it now! I understand that maybe you are getting frustrated helping me :frown: but what can I do, I do try these myself...

Okay so I'm still trying to solve/understand this question... Just to summarize, this is ALL I have (sadly): sin2t - cost > 0 2sintcost - cost > 0 cost(2sint - 1) > 0 therefore --> cost >0 AND sint>1/2 ALSO: sin2t - cost < 0 2sintcost - cost < 0 cost(2sint - 1) < 0 therefore -->...

OKAY so: 27ycos\theta = -(sin\theta)x + 2sin\theta x-intercept: let y=0 0 = -sin\thetax + 2sin\theta (sin\theta)x + 2sin\theta x = (2sin\theta)/sin\theta y-intercept: let x=0 27ycos\theta = 0 + 2sin\theta 27ycos\theta = 2sin\theta y = 2sin\theta/27cos\theta Sum of x- &...

Uhm, okay so I just wrote the entire question out again and tried to find out what 'the sum of the x and y intercepts' means but I cannot get any further with my problem :(

:cry:could you maybe just reword it or something? sorry I know you've helped me loads but it seems to be hard for me understand what the question is asking for:frown: I'm german :redface:

Oh I see what you did there, you converted cot to sin/cos...genius :D so now this is the equation for the tangent line, awesome...next problem, what am I supposed to do for part (c), what is the question asking for? the Sum of the x and y intercepts?

hey you, thanks a lot! So when I plug it into y=mx+b I get: sin(theta)=(-1/cot(theta))cos(theta) + b is this the answer to part (b)?? what is (c) asking for here?! calculus is another language! :(

hi mark, I just cannot see how my y is wrong?! Here's what I did: (x^2/27^2) + y^2 = 1 y^2 = 1 - (x^2/27^2) y =sqrt{ 1 - (x^2/27^2)} Would I now plug in 27cos(theta) for my x? But what is theta? All I know about the tangent line is y = (-1/27cot(theta))x + b --> to find b I habe to plug in...

oh wow, I seem to be too stupid for this one today, I think I'll try some more tomorrow:frown: I think what might be throwing me off a bit might be that on the x-axis for the curves the values are \pi /2 etc and not just real numbers like (4, 8.5) lol ya...its been a couple of years since high...

[SIZE="5"]Woohoo!:!)

Yes, Mark that is the equation of the conic given. The only part of the question I did not type out is the first part: You are living in a time just before Newton ad Leibniz. One night as you sleep, you have dream involving the conic: x2/272 + y2 = 1 I didn't think it mattered lol