Potential Difference and Velocity
E = Vq
→0.5mv^2=Vq
→v = √(2Vq/m)
OR
→V=0.5mv^2/q
where
V-potential difference
m-mass of the particle
v-velocity of the particle
E-energy of the particle
q-charge on the particle
Homework Statement
Two particles A and B having equal charges +6C, after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular path of radii 2 and 3cm repectively. The ratio of mass of A and B is ______
Homework Equations
Force...