I think I got it.
I let ##\hat{A}## be represented by a matrix in the given ON basis. This gave me a 8x8 matrix with mostly zeros. I then calculated the eigenvalues to:
$$\lambda_1 = 0, \ \lambda_2 = \frac{1}{1+\sqrt{2}}, \ \lambda_3 = \frac{1}{1-\sqrt{2}}, \ \lambda_i = 0 (i=4,5,6,7,8)$$...