Recent content by Anyua

Ok! Oh my goodness, thank you sooo much for your help! Sorry for getting so confused, this is my first semester taking physics ever! Luckily I got the college physics course without the calc, haha. Thank you!

And then I'd plug that back into y = 28.2 m/s * sin(45) - 9.8 m/s^2t? t= (28.2)(sin45)/9.8 = 2.03s?

Ok, so: v0sin(45)/4.9m/s2 = 81.1m/v0cos(45) 4.9m/s2/v0sin(45) * 81.1m/v0cos(45) v02 = 4.9m/s2/sin(45) * 81.1m/cos(45) v0 = 28.2m/s?

81.1 = v0x x t. 81.1 = v0cos(45) x t 81.1/v0cos(45) = t?

Haha, ok - so I would have y, which = 0, = v0sin(45)t - (4.9 m/s2)t2. Then v0sin(45)t = (4.9 m/s2)t2 since my other side is equal to 0. Then v0sin(45)t/(4.9 m/s2)t2 and multiply out my single t to get v0sin(45)/4.9 m/s2 --- is that right?

Ok, so then I am still stuck on the initial vertical velocity, because I would have to use that to find v0y, right? I am still thinking it's 0. If so, I would turn the problem around to t=\sqrt{}-4.9 m/s2\sqrt{} but that is wrong...argh...

Hmm...I thought it was y=v0t-0.5gt2...? I am really bad at manipulating these formulas to work for me :( the x and y components are vx= v0cos(0) and vy = v0sin(45) - (9.8m/s2)t ? Is my initial vertical velocity gravity?

The problem: The record distance in the sport of throwing compats is 81.1m. This record toss was set by Steve Urner of the US in 1981. Assuming the initial launch angle was 45 degrees and neglecting air resistance, determine a) the initial speed of the projectile and b) the total time the...