Homework Statement
A pair of slits separated by d = 1.30 mm is illuminated with light of l = 610 nm wavelength and falls on a screen L = 2.00 m away. A piece of glass with index of refraction n = 2.2 is placed at one slit. If the maxima shift is Dx/2, and falls on a minimum, what was the...
Homework Statement
The distance between the movable mirror and the beam splitter in a Michelson interferometer is increased a small amount. What this happens, you see 200 dark fringes move across the field of view. If the incident light was 600nm, by how much was the mirror moved (in...
The problem states:
A loop of area 4cm^2 has its plane parallel to the field lines of the magnetic field, B = 0.6t, as shown in the figure. The loop is pulled in the opposite direction of the field with a constant velocity of v = 6m/s.
I am confused as to solve this because I can't...
I have a few general questions which I need some clarification on.
1. What is really the relationship between potentials and test charges? I know how they relate to capacitance, but not really to each other. For example would a charge of 5mC be drawn to a potential of -7V or 7V?
2. I know...
I was using the Fx equation. That was my first one. However I wasn't using Fy. I'm not sure how to use it in this senario. F(e) I was using as electric force. I don't have a theta key so I just used 'q' as a dummy variable.
I was then using q=(F(e)r^2/k)^1/2. I knew that the length of my string was 1.2 meters, so I used tan(42.6)(1.2)=1.10 for half the radius between the two balls. However when I plug all these numbers in I get 1/95x10^-11 which is too small.
Alright it sounds like we're on the same tract so I'll post my equations.
F(x)=F(e)-Tsin(q)=0
F(e)=Tsin(q)=mgsin(q)=(.012)(9.81)sin(42.6)=.0797 N (I just realized my calculator was in Radians, not degrees from my Calc class, but let's please continue because I want to make sure I understand...
Mine differs just slightly. There are two balls that form a triangle and the angle taken is from the horizontal splitting the angle formed by the two strings, but the angles equal. I noticed your first equation uses the opposite sign of what I used, but is that significant enough to change my...
Alright I tried to do what you told me.
x-direction: F(tension)cos(q)-F(electric)= 0
y-direction: F(tension)sin(q)-mg= 0
Solving for F(tension) I can then use F(electric)=kq^2/r^2 to solve for q. Q=(F(electric)r^2/k)^1/2. However something I am doing is wrong because when I plug in...
Since the balls are equal in charge the force is directed away from each other.
F(y) =mg =(.012)(9.81) and F(x) =mgcos(q) =(.012)(9.81)cos(42.6)
Is this even close?
I know that the forces acting on the balls are gravity and string tension, but I do not think they are moving. There is a diagram with the problem that shows the two balls hanging, each with a 42.6 degree angle from vertical. Doesn't this mean that they are suspended on some sort of wire and not...
Homework Statement
Two small pith balls, each of mass m = 12 g, are suspended by 1.2 m fine (so that we can neglect their mass in this problem) strings and are not moving. If the angle that each string makes with the vertical is q = 42.6, and the charges on the two balls are equal, what is...
Okay I'm more confused now. I know about about the logorithmic scale thing. But I also know that since dB=10 log(I2/I1) Going down 3dB is equivalent to decreasing by a factor of two since 10 log(2)=dB. I also know that every 10dB the intensity doubles. So I don't understand how 10dB increases...