Recent content by Apollinaria

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    Finding simplest radical form of a 4th root?

    I haven't taken math in years and am having trouble understanding how to find simplest radical form of a 4√(x14). I said x4√x10. I realize I have 3 x4ths and x2 but I'm not sure if I can pull out more xs. What are the rules for this? Ideas, insight?
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    Gravitational force problem: finding r

    Doc, I think I misinterpreted what you said... The r2 goes under the mE. The (d-r)2 goes under the ms I did it this way and got the correct answer.
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    Gravitational force problem: finding r

    Different attempt. Also, how can the mass of the ship cancel out if there's only one of them in the numerator and 2 in the denominator? My algebra is rusty. Edit: I didn't get the correct answer using this method. I don't know if its the calculations or if I didn't isolate properly.
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    Gravitational force problem: finding r

    Negative. Yeah, I have no idea.
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    Gravitational force problem: finding r

    Oooooo, I think I have it..... Sec.
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    Gravitational force problem: finding r

    Sorry, office with scanner in it is occupado. Had to take a crappy photo. I haven't learned how to use the forum sqrt thingies and such yet. Will get on that later. Edit: WOW, worser quality than I thought. d√(Gmsmship) - r√(Gmsmship) = r√(GmEmship)
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    Gravitational force problem: finding r

    Can't I cross multiply to get rid of the denominators?...
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    Gravitational force problem: finding r

    I see what you're saying now. So, what I'm actually looking for is d and not r? I will multiply it out in a few min. Also, does it matter which is the r and which is the d-r? Or can I attach it to either expression? :P And, will the denominator be (d-r)2 OR (d-r2)2? :uhh:
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    Gravitational force problem: finding r

    Hi Tim! :) I was hoping to avoid using the quadratic because we haven't used it this semester, nor does he encourage it. I will be a few moments...
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    Gravitational force problem: finding r

    Hey there :) I was browsing online for solutions. Google, yahoo, youtube, everywhere and I found alternatives of it solved as a quadratic but those don't help me either and I'd rather not go there :rofl: I see what you did there now! But I still can't begin to imagine how r is isolated. I've...
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    Gravitational force problem: finding r

    Hi PF, this problem came up in my homework assignment 2 months ago and the assignment online shows a solution that includes the correct formula. However, I still don't understand how to do the problem or how the formula is derived. A similar question is also on one of my worksheets and the...
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    Do not understand the question: Projectile motion (got correct answers)

    So Vfy will be zero because the ball briefly stops before it comes down. And Viy is what we initially found for the y component (42sin60). I'm just confused as to why we're not using 42m/s as our Vi instead of the y component. Ughhh :grumpy:
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    Do not understand the question: Projectile motion (got correct answers)

    I had no idea that a=0 for projectile motion. Thanks for that bit of info. So you're saying that if I had a time for H, I could plug that in to find H? I need to rephrase my own question.. :blushing: Why is 42sin60 Viy? Is Viy same as H? Or same as Diy? I wasn't sure what I was finding there...
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    Conservation of momentum theory question

    Lol, okay, thanks very much for your help :)
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    Conservation of momentum theory question

    How do we end up with people/objects going in different directions upon collision then? I've done those types of questions too. Sometimes I get the correct answer and sometimes I don't. I'd like to know a way of recognizing the problem.
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