Recent content by Apollinaria

I haven't taken math in years and am having trouble understanding how to find simplest radical form of a 4√(x14). I said x4√x10. I realize I have 3 x4ths and x2 but I'm not sure if I can pull out more xs. What are the rules for this? Ideas, insight?

Doc, I think I misinterpreted what you said... The r2 goes under the mE. The (d-r)2 goes under the ms I did it this way and got the correct answer.

Different attempt. Also, how can the mass of the ship cancel out if there's only one of them in the numerator and 2 in the denominator? My algebra is rusty. Edit: I didn't get the correct answer using this method. I don't know if its the calculations or if I didn't isolate properly.

Negative. Yeah, I have no idea.

Oooooo, I think I have it... Sec.

Sorry, office with scanner in it is occupado. Had to take a crappy photo. I haven't learned how to use the forum sqrt thingies and such yet. Will get on that later. Edit: WOW, worser quality than I thought. d√(Gmsmship) - r√(Gmsmship) = r√(GmEmship)

Can't I cross multiply to get rid of the denominators?...

I see what you're saying now. So, what I'm actually looking for is d and not r? I will multiply it out in a few min. Also, does it matter which is the r and which is the d-r? Or can I attach it to either expression? :P And, will the denominator be (d-r)2 OR (d-r2)2? :rolleyes:

Hi Tim! :) I was hoping to avoid using the quadratic because we haven't used it this semester, nor does he encourage it. I will be a few moments...

Hey there :) I was browsing online for solutions. Google, yahoo, youtube, everywhere and I found alternatives of it solved as a quadratic but those don't help me either and I'd rather not go there :smile: I see what you did there now! But I still can't begin to imagine how r is isolated. I've...

Hi PF, this problem came up in my homework assignment 2 months ago and the assignment online shows a solution that includes the correct formula. However, I still don't understand how to do the problem or how the formula is derived. A similar question is also on one of my worksheets and the...

So Vfy will be zero because the ball briefly stops before it comes down. And Viy is what we initially found for the y component (42sin60). I'm just confused as to why we're not using 42m/s as our Vi instead of the y component. Ughhh

I had no idea that a=0 for projectile motion. Thanks for that bit of info. So you're saying that if I had a time for H, I could plug that into find H? I need to rephrase my own question.. :blushing: Why is 42sin60 Viy? Is Viy same as H? Or same as Diy? I wasn't sure what I was finding there...

Lol, okay, thanks very much for your help :)

How do we end up with people/objects going in different directions upon collision then? I've done those types of questions too. Sometimes I get the correct answer and sometimes I don't. I'd like to know a way of recognizing the problem.