Recent content by aporter1

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    Prove the impossibility of construction with ruler and compass the numbers:

    Homework Statement ∛4 ∛5 ∛3 and ∛a Homework Equations The Attempt at a Solution I have started with the problem but i feel like I'm off track. I'll upload a pic of the work so far.
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    Proof by induction of the sum of 2 squares

    its one class, and i got good grades in the pre requisites. but see its an independent study class where its a special topics class, so my teacher just randomly picked a book
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    Proof by induction of the sum of 2 squares

    so I'm on the right track for the right side then?
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    Proof by induction of the sum of 2 squares

    so I've gone along with assume: rk=(a2+b2) if, rk+1=(a2+b2)(c2+d2)=(ac-bd)2)+(ad+bc)2
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    Proof by induction of the sum of 2 squares

    so I'm thinking this is how i start, r= (a2+b2)(c2+d2)...n=(ac-bd)2+(ad+bc)2 am i on the right track?
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    Proof by induction of the sum of 2 squares

    okay but what I'm confused with is how do I end up substituting n in?
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    Help with a discrete math homework problem

    would i add r2+s2 to both sides?
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    Help with a discrete math homework problem

    its greater than zero because there are fractions
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    Proof by induction of the sum of 2 squares

    I've taken history of math discrete math, but its been a while. Its a 400 level course, its an independent study class. I've gone to my teacher for help but I don't understand
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    Help with a discrete math homework problem

    so how do i go about doing that then? I have to start with: 2/[(1/r)+(1/s)]2
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    Proof by induction of the sum of 2 squares

    no because where do i substitute the 2 into? i needed a n term in there to be able to put the 2 in
  12. A

    Proof by induction of the sum of 2 squares

    okay so I'm starting to prove by induction, let a1 be related to (a2+b2) and a2 be related to (c2+d2) so we have : r=(a2+b2)(c2+d2)...n(n+1)= (ac-bd)2+(ad+bc)2
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    Help with a discrete math homework problem

    well I was just comparing it to the other part in the problem
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