Homework Statement
In 1991, Doug Danger rode a motorcycle to jump a horizontal distance of 76.5m. Find the maximm height of the jump if his angle with respect to the ground was 12.0?.
Homework Equations
Initial Velocity= ?g?x/2(sin ?)(cos ?)
?t= ?x/vi(cos ?)
?y= vi(sin ?)?t+1/2g(?t)^2
The...
Did not really throw me off, questioned it, but hey that's how it goes. Your equation will probably eliminate the percentage of error I am getting when entering this into my calculator...
What really threw me off, was having my teacher telling me this was an incorrect method of solving it, and...
final vertical velocity= (-g)(√-2∆y/-g) (This is assuming that the object had no vertical velocity to begin with)(I just derived this equation from two that I know...so correct me if I am wrong)=-6.9 m/s
Pythagorean Thereom= a^2+b^2=c^2
a=√c^2-b^2
=9.8 m/s99% sure this is correct- so correct...
I do know the horizontal component?
Given:
-The angle launched is 0 degrees, correct?
-Vertical displacement 2.45m
Final velocity= 12.0 m/s
Again I'm pretty much out of ideas.
I am completely and utterly confused at this point. What I believe I am sure of.
-The horizontal motion is constant, since we are not taking into account fluid friction.
-The only component being accelerated is thus the vertical velocity, the force accelerating it is gravity...
-The initial...
This is a problem which, allegedly requires use of a trigonometric equation (so I've heard, but it is extra credit and thus no help beyond that will be given...)
The problem:
Libyan basketball player Suleiman Nashnush was the tallest basketball player ever. His height was 2.45 meters...
Let me start off by saying I'm not 100% certain that this is the correct forum for this to be posted in, if I'm incorrect in doing so, I apologize.
I've found several threads previously discussed about mousetrap cars, none of which answer the questions I have.
I have four days to design...