Recent content by Arait

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    Double pulley problem-difference in acceleration

    I think I kinda see it now. Thanks!
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    Double pulley problem-difference in acceleration

    I got it right by taking 958-(small mass)(g)=(small mass)(a). I got a=12.99 m/s^2. So, my homework is now done, but even though I figured out the right number, I'm still conceptually having a problem seeing the difference between Case A and Case B.
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    Double pulley problem-difference in acceleration

    I'm betting it's not... But I don't know how to calculate it.
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    Double pulley problem-difference in acceleration

    I don't know. It's the opposite of gravity? I know that doesn't work since there's acceleration other than gravity acting in the downward direction, but I don't know how to solve for tension when there are so many variables you don't know.
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    Double pulley problem-difference in acceleration

    I found something in my book that says that a the force T applied at one end of amassless rope is transmitted undiminished to the other end. Does this mean that T=958 N on both sides?
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    Double pulley problem-difference in acceleration

    I'm still lost. The mass of the hand is probably different from the mass of the block, but as long as the force is the same, I don't see how it would change anything.
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    Double pulley problem-difference in acceleration

    Double pulley problem--difference in acceleration Homework Statement http://img339.imageshack.us/img339/8793/picture1jv.png Uploaded with ImageShack.us Homework Equations a= g(M-m)/M+m The Attempt at a Solution Okay, so overall, pulleys just confuse me. We barely mentioned...