Recent content by Aralox

Ohhhhh now i understand! I've always had this idea in my head that when taking the net force they must all act at the same point, but now i think about it, that can't be the case. Thank you for all the help Redbelly98! :)

Just a little bump :)

Alrighty, so if i had: \sum F = N - mg = ma, which leads to N = (5/3)mg would N be the 'vertical component of reaction at the pin'? Isnt N the force (reaction force of some sort) vector originating at the centre of the disc, since I am taking net force at the centre?

Thanks for the reply! 1. Given I, and the torque about the pivot point, can you calculate the angular acceleration of the disk? I used Net Torque = mgr, as initially the weight is perp. to radius to pivot. Since net torque = Iα (α is angular acc.), mgr = Iα. Since I = (3/2) mr^2, I...

Hi guys, I am really stumped by this 1st yr Dynamics question, and would appreciate any help on how to approach the question. Homework Statement Homework Equations Torque equations and Force equations Moment of inertia for disc rotating around centre: (mr^2)/2 After using parallel...