Recent content by Aravsion

gneill Big thanks! :smile: I solved it like this, if my thinking was wrong please correct me: 8 \textup{ V} = 0.04 \textup{ m} - This is because we know that the distance between the top and bottom plates is 0.04 meters and the difference in potential difference is 8 volts. 1 \textup{ V} =...

gneill Thank you :) now I understand.. The answer I got was 75%... Also, how would I approach the 2nd problem, do you have any ideas?

Power = UI so the power of the motor is - Power = 120 \textup{ V}\times 0.5 \textup{ A} and this equals to 60 watts. How can I find the time though? Also, from lifting the 9 kg mass at a velocity of 0.5 m/s I can convert the 9 kg mass to its weight (9 kg * 9.8 m/s2) and then simply multiply...

The equation for mechanical work is Work = force x distance and for electrical it's Potential difference (V) x q (charge) = Work or Potential energy difference of the charge... Is that what you're asking? E = F/q and also E = V/d

I have two problems that I have difficulty understanding and solving. Homework Statement The operating efficiency of a 0.5 A, 120 V electric motor that lifts 9 kg mass agaisnt gravity at an average velocity of 0.5 m/s is most nearly what percentage? Please help me solve this problem 2...