gneill
Big thanks! :smile:
I solved it like this, if my thinking was wrong please correct me:
8 \textup{ V} = 0.04 \textup{ m} - This is because we know that the distance between the top and bottom plates is 0.04 meters and the difference in potential difference is 8 volts.
1 \textup{ V} =...
Power = UI so the power of the motor is - Power = 120 \textup{ V}\times 0.5 \textup{ A} and this equals to 60 watts. How can I find the time though?
Also, from lifting the 9 kg mass at a velocity of 0.5 m/s I can convert the 9 kg mass to its weight (9 kg * 9.8 m/s2) and then simply multiply...
The equation for mechanical work is Work = force x distance and for electrical it's Potential difference (V) x q (charge) = Work or Potential energy difference of the charge... Is that what you're asking?
E = F/q and also E = V/d
I have two problems that I have difficulty understanding and solving.
Homework Statement
The operating efficiency of a 0.5 A, 120 V electric motor that lifts 9 kg mass agaisnt gravity at an average velocity of 0.5 m/s is most nearly what percentage?
Please help me solve this problem
2...