I have solved my problem.
All I did was that:
da/dt = da/dm1 ⋅ dm1/dt = [(m2+m1)(-1)-(m2-m1)(1)]/(m2+m1)2 ⋅ dm1/dt
da/dt = g [-2m2/(m2+m1)2] ⋅ dm/dt
da/dt = (-3.92)[m2/(m2+m1)^2]
a) at t=0; m1= 1.3
da/dt= 0.653 m/s^3
b) at t=3; m1=1.3-0.2(3)=0.7
da/dt= 0.896 m/s^3
c) if m=0; a=max
m - 0.2t =0...
Homework Statement
Two containers are connected by a cord (of negligible mass) passing over a frictionless pulley (also of negligible mass). At time t = 0 container 1 has mass 1.3 kg and container 2 has mass 2.8 kg, but container 1 is losing mass (through a leak) at the constant rate of 0.200...