Yes, hotvettes example was clear. I figured that the known y-coordinates has their counter parts aas below.
y1=-y4 and y2=-y3
Isn´t it only one ellipse that fits these four points?
Yes, let's say the ellipse centered in origo. In that way I have only two unknonwns.
As I said only that matters are the length of the semi-axes.
If know the two points exactly it easy to calculate a and b. But I know y-coordinates and the difference of x-coordinates.
My mind says that...
Yes. The ellipse is origo centered and the axes are parallel to x/y axes. In addition i know the y-coordinates of two points and difference of the x-coordinates. That should be it.
Is it possible to define the semi-axes?
But if I have two points ie (1;4,71) and (2:3,73)
If I put these to the formula which is obtained from pair equation of an ellipse (x1;y1 and x2;y2):
(x1^2)/(a^2)+(y1^2)/(b^2)=1
(x2^2)/(a^2)+(y2^2)/(b^2)=1
Calculate b^2 and put to the latter...
I have been struggling for a while now with this one.
Lets say I have two points on the arc of the ellipse. I know the y-coordinates and the difference of the x-coordinates. Is it possible two calculate the equation or the semiaxes of the ellipse where these points are located?
These are the...
I have been struggling for a while now with this one.
Homework Statement
Let's say I have two points on the arc of the ellipse. I know the y-coordinates and the difference of the x-coordinates. Is it possible two calculate the equation or the semiaxes of the ellipse where these points are...