Recent content by AROD

when can you say that the voltage in the loop will be zero? not in this case?

are you saying just ignore those 6 connections?

first node brances to 3, each of those branch twice, 6 branches then converging on 3 nodes, which tnen go back to 1 node. since all resistors are equal, can the 3 node to 3 node connection be just expressed as 3 parallel with 2 each? my reaction is to make each little group of 2 parallel...

Homework Statement I have a network of resistors in a box-formation. There is 1 resistor of equal resistance in between every corner of the box, so 12 in total. Homework Equations In series R = r1 + r2 + ... ri In parallel, 1/R = 1/r1 + 1/r2 + ... 1/ri The Attempt at a Solution...

gotcha, my bad. physics rocks.

my attempt a) mgh=(60)(9.8)(1500) =882000 joules=882 kJ If she works at 25 % efficiency, she must do 4 times the work, or 4*mgh= 3528 kJ 4.184 kJ=1 kilocalorie => 3528 kJ= 843 kilocalories==> 8.43 ounces or 8.43 bowls of corn flakes 3/4 energy from the corn flakes is 3*882 = 2646...

distance needed to get to vmax, s = (vmax^2 -vi^2)/2a or what? can't just do the reverse for the other distance because s1 + s2 will cancel each other out.

ok so then its just mgh with h = L/2 . that makes sense then as it tips the hypotoneuse would be L/2, and the height would be this times the cos of theta. thanks

Homework Statement Homework Equations Rotational Kinetic Energy = 1/2*I*w^2 The Attempt at a Solution I was just wondering if someone explain to me why the potential energy is MgL/2 ? Is this not the same for the torque from gravity?

moment of inertia for this disk is 1/2*(mass disk)*r^2 and before with the man on the edge the total inertia is plus also 1/2*(mass man)*(position)^2 ? and at the end the man is in the center so his distance from center of mass is 0 and doesn't contribute to the intertia, just the total mass

Homework Statement A man (mass m1 = 100 kg) stands at the fringe of the large rotary table (radius R = 5 m, massm2 = 100 x m1), which rotates at a frequency of 10/min. The man goes along a radius line towards the table center until he reaches the rotation axis. The spatial extent of the man...

Hmmm how would you set up the following situation in conservation of momentum terms? A young physicist weighing 80 kg enjoys the sunset together with his girl friend on a rowboat floating on a calm lake. The boat weighs 30 kg and does not move. The young couple swap their seats which are...

total energy stored in the oscillation would just be mgh at the heighest point or 1/2 mv^2 at the lowest then, eh?

angular velocity of the satellite and the Earth will always be the same, w = 2pi/(time in a day) orbital velocity must mean the angular velocity x the radius, [w x (height above Earth + radius of earth)] the satellite will follow a certain point on the Earth at this point. my question is: how...

so beautiful and so serene!