Recent content by Aromire

Can you just tell me how to set it up and I'll be okay, please? I know how to solve for capacitance in series; 1/C = 1/c1 + 1/c2 ...

Yes the images does make sense! Will my final answer be 7.9μF after the foil is in place? Thanks once again.

I'm more lost now. I'm sorry but do we got to deal with the charges in respect to this question though? Please I need your help... Thanks once again

I'm not sure of what you are talking about but would it be that the capacitors are connected in series and since there is a negligible thickness, the capacitance before the foil was inserted will be the same as after the foil is in place? Please I am quite confused. If you can just kindly give a...

For distance 1, I added the position 1/2 + another 1/2 to make 1 d.

A sheet of gold foil (negligible thickness) is placed between the plates of a capacitor and has the same area as each of the plates. The foil is parallel to the plates, at a position 1/2 of the way from one to the other. Before the foil is inserted, the capacitance is 7.9μF. What is the...

Thank you very much Dopplershift, you are a life saver and I actually spent hours trying to figure it out.

Homework Statement An object starts from rest with an acceleration of 2.0 m/s2 for 3.0 seconds. It then reduces its acceleration to 1.0 m/s2 for 5.0 additional seconds. The total distance covered is Homework Equations The Attempt at a Solution I've tried using the formula of velocity =...