A sheet of gold foil (negligible thickness) is placed between the plates of a capacitor and has the same area as each of the plates. The foil is parallel to the plates, at a position 1/2 of the way from one to the other. Before the foil is inserted, the capacitance is 7.9μF. What is the capacitance after the foil is in place? What I tried: distance 1 (d1) = 1/2 + 1/2 (d) = 1 d distance 2 (d2) = 1/2 d C1 = EA/d C2 = EA/ 0.5d 1/Cs = 1/C1 + 1/C2 = 1/ (EA/d) + 1/ (EA/0.5d) = 3d/ EA Since 1/ Co = d/EA 1/Cs = 3/ 7.9 Cs = 2.633 Is this right please?