Recent content by Arrhenius7991

I'm not seeing this integral then.

Homework Statement A rod lies on the x-axis with one end at the origin and another at x=2. The linear charge density is given by λ(x)=C(x^(3) + 3x^(2)). Find the x-component of the electric field Ex at the origin in terms of q. Homework Equations Ex = ƩdEx ||dE||= (k|dq|/r^(2)) (z/r)...

Torque would be mgrsinθ, r being the radius of the ring.

You'd multiple the force by the distance the point is from the center of mass. Given by r. So, Torque=vector(r) x(Cross-Product) F(Force).

Ok. So now what?

T(Torque) = -κθ. And α(alpha)=angular acceleration=ω^(2)x(max), ω=angular speed, and x(max) is the amplitude.

Ʃ(Torque)=Iα From Newton's Second Law: (Torque)=mgsinθ And I is given by Parallel Axis Thm: I=I(COM)+MR^(2), and I(COM)=MR^(2), the moment of inertia for a thin ring. α=ω^(2)x(max) ω=√(κ/I)=√(κ/2MR^(2)) So, Mgsinθ=(2MR^(2))(ω^(2)x(max)) Mgsinθ=(2MR^(2))((κ/(2MR^(2))x(max))...

Homework Statement Apply the physical pendulum equation to a ring pivoted on its edge to derive the equation for the period of a ring pendulum for small oscillations about the pivot point. Include a diagram showing the restoring torque acting on a ring pendulum displaced from equilibrium...