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How to Integrate dz/ (y^2 + (x-z)^2))^1/2 Using Inverse Hyperbolic Functions?
Thank you for the reply, but there is a square root at the denominator (y^2+ (x-z)^2)^1/2. I know the answer of this derivation, with respect to limits 0 to L, Integral of dz/ Square root of (y^2+(x-z)^2) = ln (x+ Square root of (x^2+y^2)/ x-L + square root of...- Arthy
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- Forum: Calculus and Beyond Homework Help
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How to Integrate dz/ (y^2 + (x-z)^2))^1/2 Using Inverse Hyperbolic Functions?
Integral of dz/ (y^2 + (x-z)^2))^1/2- Arthy
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- Forum: Calculus and Beyond Homework Help