Ok. Never mind. Solved!
Just posting this for anyone who's interested..
So..
x= u cos Ɵ t
Thus,
t=x/(u cos Ɵ)... eq1
y= u sin Ɵ t + (gt^2)/2... eq2
Substitute the t in eq2 with eq1, you'll get this:
y= x tan Ɵ + (x^2 g)/(2 u^2 cos^2 Ɵ)
y/x= tan Ɵ + [(x g)(1 + tan^2...
How do I continue on? I've tried and I came up with something but I don't think I did it right.
By comparing both equations and using the y=mx+c concept
eq 1: y/x=[g(1+k^2)x]/(2u^2) + k
eq 2: y/x= tan Ɵ + (gt^2)/(2u cos Ɵ t)
So..
tan Ɵ= k
and
[g(1+k^2)]/(2u^2) = (gt^2)/(2u...
Hi guys,
I have some questions about this equation that my class were given before carrying out our practical for projectile motion (what we did was release a marble from the top of an inclined ramp and then when it hits the board which has a piece of carbon paper on it, a mark is left on a...