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I have some questions about this equation that my class were given before carrying out our practical for projectile motion (what we did was release a marble from the top of an inclined ramp and then when it hits the board which has a piece of carbon paper on it, a mark is left on a piece of paper under the carbon paper..)

Here's the equation:

**y/x=[g(1+k^2)x]/2u^2 + k**

k is a constant

g=gravitational acceleration

y=vertical distance (between bottom of ramp and top of board)

x=horizontal distance (between plumline and mark on paper)

**Questions:**

1. What is k really? (I read from some other sites that k is air resistance. Is that true?) From what equation was it derived from?

2. How do I get this equation?

1. What is k really? (I read from some other sites that k is air resistance. Is that true?) From what equation was it derived from?

2. How do I get this equation?

What I've come up with so far..:

y=(u sin Ɵ)t + 1/2 gt^2

x= u cos Ɵ t

y/x= [(u sin Ɵ)t+1/2 gt^2]/(u cos Ɵ t)

simplified it.. and I ended up with

y/x= tan Ɵ + (gt^2)/(2u cos Ɵ t)

So yeah, I'm stuck here.

Help please?

Not sure whether I'm on the right track..