Recent content by Artie

Okay I think I got it! Since all of the components are equal to 1, you can set them equal to each other. And you end up with x=y=z=t. So you plug that into the constraint function g(x,y,z,t)=400, substituting x for all the other values. And you get (x^2)+(x^2)+(x^2)+(x^2)=400. And from there...

Okay I think I got it! Since all of the components are equal to 1, you can set them equal to each other. And you end up with x=y=z=t. So you plug that into the constraint function g(x,y,z,t)=400, substituting x for all the other values. And you get (x^2)+(x^2)+(x^2)+(x^2)=400. And from there...

Okay I think I got it! Since all of the components are equal to 1, you can set them equal to each other. And you end up with x=y=z=t. So you plug that into the constraint function g(x,y,z,t)=400, substituting x for all the other values. And you get (x^2)+(x^2)+(x^2)+(x^2)=400. And from there you...

are you talking about lambda? if so, i don't know an equation for that which doesn't include atleast one other variable

okay so, for each component: 1=λ2x 1=λ2y 1=λ2z 1=λ2t

Sorry, I forgot that there was a designated spot for homework questions. But yes I've looked all over the internet for how to do this problem. So what is the next step? I know how to use Lagrange multipliers for just two variables, f(x,y), but I don't understand how to use it for four.

Homework Statement Find the maximum and minimum values of the function f(x,y,z,t)=x+y+z+t subject to the constraint x^2+y^2+z^2+t^2=400. Homework Equations I think the Lagrange multiplers can be used ∇f=λ∇g The Attempt at a Solution So I found ∇f=<1,1,1,1> and ∇g=<2x,2y,2z,2t> and...

why do we ignore the +/- v when solving for d?

Okay, thank you! Sorry I second guessed you :/

Oh okay. So the d= v2/2(a1+a2) right?

Oh but I think the prompt called for us to find distance in terms of velocity and acceleration, instead of finding time

Hey sorry to bother you again since we kind of already finished this conversation. But I just wanted to clarify, do you assume that the ±v is 0?

Okay, I see! This answer was actually do a couple days ago and I got it wrong haha, but I still wanted to understand how to do it. Thank you for all of your help! I couldn't have done it without you :) I hope you have a fantastic night!

Oh ya, I forgot about the 1/2. Well because the prompt specifically states that it is moving in the positive x direction, does that mean that we pick which ever equation would come out positive?

Okay that equation did not turn out the way I expected. But basically I just did the quadratic equation