Recent content by ash25
-
A
Proofs using contrapositive or contradiction
Thank you very much! My head can now stop hurting! :) I knew I was over thinking this problem I really appreciate your time! Thanks again!- ash25
- Post #11
- Forum: Calculus and Beyond Homework Help
-
A
Proofs using contrapositive or contradiction
This is one of the first problems that I completed from this long assignment. The equations y=-x^2 and y=-x+5 have no real solutions in common. Proof:Suppose the 2 equations y=-x^2+2x+2 and y=-x+5 have at least one real solution,c. → -c^2+2c+2=-c+5 →c^2-3c+3=0 →c=(3±√(9-12))/2...- ash25
- Post #7
- Forum: Calculus and Beyond Homework Help
-
A
Proofs using contrapositive or contradiction
I haven't been working on this particular problem for hours, I have been working on the entire assignment for hours and I think that I am starting to blend everything together.- ash25
- Post #5
- Forum: Calculus and Beyond Homework Help
-
A
How to Correct an Incorrect Proof Involving Set Theory?
You are being so helpful thank you! but you are saying that the claim is false?- ash25
- Post #5
- Forum: Calculus and Beyond Homework Help
-
A
Proofs using contrapositive or contradiction
I am so confused at this point. I have been working on this assignment for hours and I think that I am just over thinking it.- ash25
- Post #3
- Forum: Calculus and Beyond Homework Help
-
A
How to Correct an Incorrect Proof Involving Set Theory?
Thank you, so the claim was true though, right? It was: For any sets S,T,and W,if S∩T≠0 and T∩W≠0,then S∩W≠0- ash25
- Post #3
- Forum: Calculus and Beyond Homework Help
-
A
Proofs using contrapositive or contradiction
Please Help! proofs using contrapositive or contradiction Homework Statement Prove using contrapositive or contradiction: For all r,s∈R,if r and s are positive,then √r+ √s≠ √(r+s)- ash25
- Thread
- Contradiction Contrapositive Proofs
- Replies: 10
- Forum: Calculus and Beyond Homework Help
-
A
How to Correct an Incorrect Proof Involving Set Theory?
Homework Statement PLEASE HELP!How would you correct this incorrect proof: Suppose that S∩T≠0,T∩W≠0,and for a contradiction S∩W=0.From the first 2,we have some t∈S∩T,and similarly t∈T∩W.But then t∈S,t∈T,and t∈W.So t∈S∩W,giving a contradiction.- ash25
- Thread
- Proof
- Replies: 5
- Forum: Calculus and Beyond Homework Help