Recent content by Ashferico

Hello, I have designed a gearbox that bolts on to a fixed engine and fixed pump. It is completely supported by them. The total mass of the gearbox and the components attaching it to the engine and pump is 7.7kg. Its centre of mass is 0.167m along the x-axis and 0.09m along the z-axis from the...

So, in this scenario. Its just two supports, front wheels and stabilizers. The force of the stabilizer in static equilibrium is also the force to jack the vehicle up? Thus it is the force of the linear actuators? It is for a mechanical design project and I need to specify the right components.

Hi, Thank you for the reply again. Does that mean the original statically indeterminate calculation was the force required of the linear actuators?

Hi, I previously posted about the statically indeterminate truck problem. Thank you to everyone who helped me. However, I now realized that isn't the problem I need to solve. I need to know the force of the linear actuators to lift the rear tyres off the ground. Since the tyres will be...

Hello again, I have to calculate the required force of the linear actuator that drives the stabilizer leg. The 79.3kN I calculated before, if that was spread over 2 stabilizers, it would approximately 40kN per leg. If it was angled at 60 degrees like on the diagram, does that mean linear...

Yes, you're right. I've corrected it now. Thank you for your help!

Thank you! What more information on my diagram do I need to calculate the reaction forces when payload is lifted? Thank you! So I think I have applied what you mentioned. Is this what you had in mind?

Hi J Briggs, Thank you for the response. I'm not super clued up about suspensions. I would say that both axles and stabilizer legs are sprung with the same stiffness. With the last question, does that mean the stabilizer reaction force is zero? If so, I guess that makes it possible. I'm not...

If you do the sum of vertical forces and sum of moments, you're always left with an unknown. Vertical Forces: Ray + Rby + Rcy = 59kN + 45kN (1) Sum of Moments about A: (59 x 1.85) - (Rby x 3.7) - (Rcy x 4.8) + (45 x 6.5) = 0...