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Gcd(a, b, c) = gcd(gcd(a,b), c)
Help please! I basically have to prove that gcd(a, b, c) = gcd(gcd(a,b), c). So I know that if I just need to prove that the sets {a, b, c} and {gcd(a,b), c} have the same sets of divisors.- ashwinb
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- Forum: Calculus and Beyond Homework Help