Recent content by at3rg0

Correct me if I'm wrong, but aren't there more than 22.990g NaCl/mole?

Going by units alone... Shouldn't Q/(Epsilon0 * E) give m^2? All right, I tried rearranging again. A = C/(Epsilon0*E*kappa), which gives me .003762. Where am I making the mistake in formula manipulation? I used C=Q/V, where V=Ed, and C=kappa*epsilon0*Area/d

Using the formulas, I got that Area = Q*Epsilon(not)/Electric Field So Area = (8E-9)(8.85E-12)/1.3E5 = 5.45E-25 m^2 (so 5.45E-23cm^2) - I need to give the answer in cm^2.

Homework Statement Two parallel plates have charges Q and -Q. When the space between the plates is devoid of matter, the electric field is 2.7E5 V/m. When the space is filled with a certain dielectric, the field is reduced to 1.3E5 V/m. What is the dielectric constant of the dielectric? I got...

Yeah, it was easy. I just did: .5(195E-12)(3.3E3^2) + (.5(600E-12)(3.3E3^2) - Final Energy (I forget the value), and got the solution.

Okay, and I used U=.5CV^2 to get the energy. Thanks so much!

So, in parallel, they'll be added? So, divide by the sum of the two capacitances? Does that give me the voltage on both? Okay, so the answer is right. Each has 1.98kV. However, how would I account for the Energy lost?

1980microC and 495mC, right?

Homework Statement A 150 pF capacitor and a 600 pF capacitor are both charged to 3.3 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate. a) What is the voltage in kV across each capacitor? b) How much energy is lost (in mJ)...

The golden ratio is irrational. Do you know any clever proofs for this fact? I put this here, because it's not homework--only more of a discussion.

Homework Statement Igor, the inchworm, is crawling along graph paper in a magnetic field. The intensity of the field at the point (x,y) is given by M(x,y) = 4x^2 + y^2 + 5000. If Igor is at the point (8,6), describe the curve along which he should travel if he wishes to reduce the field...