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Ok so would the Force acting at C Be the Weight of the wheel plus gravity acting to pull CD down? in this case 490 N? therefore the torque must be able to balance 490 N of opposite Force? I am still unsure how to determine the force required by Arm CD acting at D to lift G, and once i determine...

Here is my attempt so far F = 50 x 9.8 = 490 N T = 500mm x 490 x sin(30) T = 122.500 I have no idea to tell if this is on ther right track or not

Homework Statement Question refers to the torque required to lift the nose wheel of an aeroplane A retracting nose wheel assembly is raised by the application of Torque T applied to link BC through a shaft B. The wheel and Arm AO have a combined mass of 50KG with a centre of mass at G. Find...