Recent content by avilaca
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Graduate Proving the Containment Property of Polar Cones for Sets in R^n
I didn't achieve a great conclusion. S* can be defined by {a \in R^{n}: x^{T}a \leq 0, for all x \in S}. Now: x^{T}a \leq 0 <=> (Ap)^{T}a \leq 0 <=> p^{T}A^{T}a \leq 0. But I can not conclude nothing about "a" from here.- avilaca
- Post #6
- Forum: Differential Geometry
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Graduate Proving the Containment Property of Polar Cones for Sets in R^n
Now another challenge: Let S = {x \in ℝ^{n}: x = Ap, p \geq 0}, where A \in M_{n*m}, p \in ℝ^{m}. What is its polar cone S*?- avilaca
- Post #4
- Forum: Differential Geometry
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Graduate Proving the Containment Property of Polar Cones for Sets in R^n
Ok, it's easy from the inner product <a,s> = ||a||.||s||cos\theta. <a,s> \leq 0 <=> pi/2 \leq \theta \leq 3pi/2. This means that if S1 \subset S2, by the above result, the region where the condition {<a,s> \leq 0 , s \in S1 or S2, a \in ℝ^{n}} is true for S1 is the same or it's larger than the...- avilaca
- Post #3
- Forum: Differential Geometry
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Graduate Proving the Containment Property of Polar Cones for Sets in R^n
Let S1*(S2*) be the polar cone of the set S1(S2) (http://en.wikipedia.org/wiki/Dual_cone_and_polar_cone). How can I show that if S1 is contained in S2 then S2* is contained in S1*. It looks obvious (especially if we think in R^2), but I do not find a way to prove it.- avilaca
- Thread
- Polar Property
- Replies: 5
- Forum: Differential Geometry