Homework Statement
The motion of a particle is expressed by a=42-12x2 where a is in m/s2 and X is in m, with the initial condition: v=0 when x=0 and t=0
Determine v when X=6
Determine X when v becomes 0 again
Homework Equations
I tried using a=dv/dt so i took the anti derivative of a...
on mass 1 we have forcetension - forcefriction + m*g = ma
mass2 -frocetension-Forcefriction2+(m*g)sin theta= m2a
the thing that's confusing me is if we could have assumed that the aceleration of B is same as acceleration of a before it hits the barrier in the diagram
http://gng1105bf2011.files.wordpress.com/2011/11/gng1105b-fall-2011_-end-of-the-trimester-assignment_due-november-25-2011.pdf question 3 I am not sure how to uplad the pictures so in this doc its on question 3a
Mechanics help :(!
I REALLY NEED HELP :(
Two blocks are connected by a cord which passes over a frictionless pulley at D.
Block A has a mass of 40 kg and block B a
mass of 120 kg. A rests on a horizontal
surface, while B rests on a ramp with the slope
shown. B is initially in a position 3...