(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The motion of a particle is expressed by a=42-12x^{2}where a is in m/s^{2}and X is in m, with the initial condition: v=0 when x=0 and t=0

Determine v when X=6

Determine X when v becomes 0 again

2. Relevant equations

I tried using a=dv/dt so i took the anti derivative of a to find the equation of v which turned out to be 42x-4x^3 + c and then pluged in 6 for x and found v=-612m/s

but then for the second part when i tried finding the roots of the equation b i have two answers +3.2 and -3.2

So i dont know if i should use +3.2 or -3.2

Can somone tell me if im doin anything wrong? :(

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Mechanical acceleration and veloctiy relationship

**Physics Forums | Science Articles, Homework Help, Discussion**