Recent content by Ayesha02

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    Calculation Involving Thermodynamics, Gravitation and Fluid mechanics

    Its JEE Advanced Exam- for entry into undergrad engineering. and the molecule won't go upto the highest point as per KE because of viscosity isn't it? Viscosity'll retard it..
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    Calculation Involving Thermodynamics, Gravitation and Fluid mechanics

    Probably. Its a competitive exam sum. how to develop thought process in such sums?
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    Calculation Involving Thermodynamics, Gravitation and Fluid mechanics

    I figured out stokes law equation but I am unable to proceed further
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    Rotational Mechanics -- A solid sphere is rolled on a rough surface

    Angular momentum conservation I got the answer:bow:
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    Rotational Mechanics -- A solid sphere is rolled on a rough surface

    Skid initially, after some time rolls. Im assuming the surface is rough
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    Rotational Mechanics -- A solid sphere is rolled on a rough surface

    I just did ##T## = 2/5 M R^2 * α which gives α =5μg/ 2R hence ##w_0(f)## = ##w_0(i)## - α t i.e 0= ##v_0##/2R - 5μg/ 2R *t hence i got t=4##v_0##/5μg (time when rotation ceases)
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    Rotational Mechanics -- A solid sphere is rolled on a rough surface

    I found out the time when rotation ceases to be 4 ##v_0## /5*mew*g, where mew=coefficent of friction of surface but I am unable to plot the graph post that time
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    Hard Momentum Conservation Impact Problem

    Yes dude got it thankyou:)
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    Hard Momentum Conservation Impact Problem

    Ohh alright then
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    Hard Momentum Conservation Impact Problem

    They can't go any further right, so shouldn't velocity be zero at that point?
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    Hard Momentum Conservation Impact Problem

    Exactly my doubt! why do they have the same KE finally as well? @PeroK could you help us?
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    Hard Momentum Conservation Impact Problem

    Nah! the final situation, as mentioned in the question, is when they're at min distance
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    Hard Momentum Conservation Impact Problem

    ohh yaa! Another thing- why don't the bodies change velocity from the initial to the final?
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    Hard Momentum Conservation Impact Problem

    an afterthought: why not conserve linear momentum?
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    Hard Momentum Conservation Impact Problem

    Okay so i gather final angular momentum should be 2(m*v*6) is that right? Im still not able to figure out initial angular momentum