im pretty sure my approach is wrong...
F = -260 * -0.8 = 208N
mg = weight
208/9.8 = m
m = 21.224489795918367346938775510204kg
im sure that's wrong is there a better way to approach this problem and why is the way I am approaching it wrong?
Homework Statement
Astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating on a large spring. Suppose an astronaut attaches one end of a large spring to her belt and the other end to a hook on the wall of the space...
alright for the next part we have perfect elastic collision
Ek = conserved
P = conserved
This is my first equation for Momentum:
m1v1+m2v2 = m1vf1+m2vf2
This is my 2nd equation for kinetic energy
1/2m1v12 + 1/2m2v22 = 1/2m1vf12+1/2m2vf22
This should take some algebra :sLooking into my...
thanks for the input D H
so, for all collisions momentum is conserved.
for elastic collisions momentum + KE is conserved
for inelastic collisions momentum is conserved but KE isn't
so the square root of 58.8 = 7.668m/s
and the final velocity of boxes stuck together is 2.56m/s
Homework Statement
A package of mass m is released from rest at a warehouse loading dock and slides down a 3.0-h frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute.
a)...
you are right the one being shot up would have the greatest Vy
Vya = sin(45)*v
Vyb = sin(60)*v
Vyc = V
What happens if the angle is 0?
There is no Vy but rather there is only Vx