Recent content by Aznhmonglor
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Potential Difference across Capacitor.
Problem solved! Thanks a million.- Aznhmonglor
- Post #7
- Forum: Introductory Physics Homework Help
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Potential Difference across Capacitor.
hmmm...Im still getting some wrong answers. So let's say for C2, I know the charge on that capacitor is 120 microCouloumbs. I am not sure what the Capacitance for it is. Would the capacitance for C2 be the sum of (1/C1)+(1/C2)=(1/Ctot)? so it would be that V=120/1.5? Just figured out this...- Aznhmonglor
- Post #5
- Forum: Introductory Physics Homework Help
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Potential Difference across Capacitor.
hmmm thanks that helps to clarify that point. So its 90 volts to C1 and the 6 microfarads capacitor and to the C2 and 2 microfarads capacitor. What equation do I need to use? I have a couple here. Looking at PE=(.5)(C)(deltaV^2) is that the right one? I think the main problem here is that I...- Aznhmonglor
- Post #3
- Forum: Introductory Physics Homework Help
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Potential Difference across Capacitor.
Homework Statement Homework Equations Not sure which equations to use but I know that we'll have to use the answers from part a and b to answer the questions. The Attempt at a Solution What I did was that I said that C1 and the 6 microfarads are parallel to C2 and the 2...- Aznhmonglor
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- Capacitor Difference Potential Potential difference
- Replies: 6
- Forum: Introductory Physics Homework Help
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How High Does the Daredevil Reach?
Does that mean I get this. 39.1=41cos(theta) Solve for theta and I get the angle to be 17.5. What do I do next? Do I do the vertical component of velocity of projection with the new angle?- Aznhmonglor
- Post #3
- Forum: Introductory Physics Homework Help
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How High Does the Daredevil Reach?
A daredevil on a motorcycle leaves the end of a ramp with a speed of 41.0 m/s as in the figure below. If his speed is 39.1 m/s when he reaches the peak of the path, what is the maximum height that he reaches? Ignore friction and air resistance. Help would be appreciated, not sure how to start...- Aznhmonglor
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- Height
- Replies: 3
- Forum: Introductory Physics Homework Help