Recent content by babamarysol

Thanks

Hi masqau, can you explain me the procedure that i found in your first link http://eqworld.ipmnet.ru/en/solutions/ode/ode0234.pdf "Selecting a sufficiently large m and omitting the term with the maximum number in the recurrence relations we can obtain approximate relations for the...

http://farside.ph.utexas.edu/teaching/qm/lectures/node25.html

can you tell me something about this \int dq_{1} dq_{2} (q_{1}^{2} + q_{1}q_{2}) exp[\mathbf{q}^{T}\mathbf{A}\mathbf{q}] ?

I'm studying Cosmology and i believe that this potential is like that of Hydrodynamics theory since we consider a perfect fluid to approximate the matter in the universe...

Why constant entropy (\dot{S}=0) implies the existence of a acceleration potential?

hamiltonian density (interaction part) \mathscr{H}_{int}=eA^\mu j_\mu two point function <0| T(\phi_1\phi_2) |0> =<0| \phi_1 \phi_2 \text{exp} \left[-i \int d^4 x \mathscr{H}_{int} \right] |0>_{connected} four point function <0|T(\phi_1\phi_2 \phi_3 \phi_4) |0>=<0| \phi_1 \phi_2...

Feynman's rules are better understood writing down the perturbation expansion for correlation's function...

Ah that's ok it's a functional derivative...

The generating functional Z[J] depends on \phi_{cl} trough its dependence on J. At the lowest order in perturbation theory the relation between J(x) and \phi_{cl} is just the classical field equation: \left(\frac{\delta L}{\delta \phi}\right)_{\phi=\phi_{cl}} + J(x) = 0 The question is...