Thanks for the response!
I'm not familiar with the antilog transform. I think I should make the following transformation:
Date -> Transformed Data
0 -> 1
1 -> 10
2 -> 100
etc..
Is this correct?
Won't this lead to some enormous numbers later? For example:
17 -> 100,000,000,000,000,000
I...
I am writing a paper publishing scientific data. My background is chemistry but I have taken a couple of stat classes. In my opinion, one of the biggest deficiencies in modern research publications is the improper use of statistics. I hope to avoid making this mistake, but I need your help...
I have a small steel cylinder centered inside a larger steel cylinder. The remaining space is filled with 60% silica sand and 40% air. I am heating the larger cylinder in a furnace at a known heating rate and I want to calculate the theoretical rate of heating of the internal cylinder. This is...
I have a block of food in an oven and I want to calculate the "cooking intensity" of the block during a controlled oven cycle. The cycle of the oven is that it heats at 5 degrees (C) per minute, holds the temperature at 300C for 1 hour, and then shuts off the oven to cool to room temperature. I...
I think I should just set theta equal to 90 degrees then, ie the limiting case. Then the pressure of interest is just the surface tension divided by the pore size. I think I just need to match this to atmospheric pressure.
Another question is whether a drop of water will have significant...
I am conducting some hydrophobicity research with dried powders. I have known mixtures of fluid from which I can calculate surface tension. I have data about the powders regarding which mixtures easily wet the surface and which bead up into drops. I also have BET surface area histograms which...
Just think of work as the amount of energy necessary to apply a force for a certain amount of time. If you want to throw a ball 5 feet, you need a certain amount of energy (or work). To throw the ball 25 feet, you need five times as much.
After you have intuition about work as a force that you...
Sorry if I'm confusing you. When I solve it, I get:
a=\frac{3}{t(1 + 3 \beta t)}
To take the derivative of 1/v the easiest thing is to invert it so you can v in the numerator.
\frac{1}{at}=\frac{1}{3}+\beta t
To check your answer, let: a= \frac{3 + \beta t^3}{3}
\frac{1}{t*\frac{3 + \beta t^3}{3}} = \frac{1}{3}+\beta t
This simplifes (sort of) to:
\frac{3}{3t+\beta t^4}=\frac{1}{3}+\beta t
Looking at the variable t, we are saying that t to the negative...
The easiest way to think about this is to break it into parts. Instead of solving for multiple unknowns just solve for part a.
The vertical component of tension must be perfectly balanced by the vertical component of the torque of the beam. Same goes for the horizontal tension.
You can...
Hmm...
That's not what I get...Assuming you start from here...
\frac{1}{at}=\frac{1}{3}+\beta t
You can check your answer by substituting what you got for a into the original equation for a (the equation above). You should get the two sides equal to each other if you have the right a...
@longball, the force exerted on the ruler will cause the ruler to spin even if it is much lighter than the ruler's weight. If the force was greater than the ruler's weight then the ruler could be "broken off" the pivot point. I think the point of the question was just to assume that the applied...
You are right that if there is no friction the ruler will continue spinning.
As for the second part, remember that there is a difference between the "ruler's motion" and the "motion of the ruler's center of mass".
Does this help?