Recent content by badbrain103

For the answer given for leucine (UCU) going to tyrosine (UAC), there would need to be one single base mutation from C -> A and U -> C. There is two single base mutations. For tyrosine (UAU) going to leusine (UUA), there would need to be a single base mutation in A in tyrosine mutating to U...

Ok sorry I haven't done electrochemistry in a long time and am a bit confused. So the solution is of AgBr mostly though it contains some small amount of H2 and Ag+ - this is because most of the Ag+ is reduced quickly, right? Because the reaction between H2 and Ag+ is so slow, it is basically...

well the two half reactions are: H2 --> 2H+ + 2e- 2AgBr(s) + 2e- --> Ag(s) + Br- giving the net ionic equation: H2 + 2AgBr --> 2H+ + 2Ag(s) + 2Br- there are no spectator ions... so...?

I have Pt(s)/H2(g)/HBr(aq)/AgBr(s)/Ag(s) The question asks why a liquid junction is not necessary. So I know AgBr is insoluble in water, and AgBr coats the silver metal. I just don't understand why it does not matter that the Br- anions from AgBr mixing with the H+ cations doesn't necessitate...