Recent content by Baharx

ok i will write again. Let A and B be two similar matrices. PAP^{-1}= B characteristic in the space λ is an eigen value, show that : length V^{A}_{λ} = length V^{B}_{λ} dimension V^{A}_{λ} = dimension V^{B}_{λ} Thanks.. probably dimension.

ok, sorry for that.

i am sorry i was trying to translate.. Size hmmm length or a scalar "norm".

Btw question 3 is maybe we can solve like this; (if its not true my solve, pls tell me.) Suppose x ∈ Nullity(A) then Ax=0 PAP^{-1}= B Bx = P^-1AP x= I. Ax = 0 → x ∈ Nullity(B) Suppose x ∈ Nullity(B) then Bx=0 Ax = P^-1BP x= I. Bx = 0 → x ∈ Nullity(A) Nullity(B) ⊆ Nullity(A). So...

thank you so much for your reply. i solved 2 and 3. yes i have to solve that way all problems : PAP^{-1}= B mean is A and B similar matrix. for 1 question; how can i write; Let A and B be two similar matrices. PAP^{-1}= B characteristic in the space λ is an eigen value, show that ...

Matrix proof :( 1. Let A and B be two similar matrices. characteristic in the space λ is an eigen value, show that : sized V_λ^A = sized V_λ^B 2. Let A invertible matrix. A ∈ ℝ nxn and invertible matrix ⇔ 0, A is not an eigen value. 3. Let A and B be two similar matrices...

but i understand. Thanks for the help. i want to study for master degree department of math. but i think i must study work hard.

Thank you, i understand but besides i wrote n>1 condition. This is why first derivative can't be find this formula. but i tried it's working 3th order and nth order :rolleyes: Thank you again.

oh, i didnt know that. i studying Calculus and that was an exercise. Leibniz? anyway. first i found on wikipedia this : http://en.wikipedia.org/wiki/Difference_quotient but i didn't understand then 6 hours i did get a fix on this exercise. Thank you for reply. but I'm seeing just sigma...

i found a formula but I'm not sure is and maybe this is exist i don't know. we know it F(x)= f(x).g(x) → F'(x)= f'(x).g(x)+g'(x).f(x) and i want to calculate nth order. n>1 fn(x).g(x)+ \sum^{n}_{k=1} binomial coefficient \left(n k\right). f(n-k)(x).gk(x)+ gn.f(x) is it true...