A mass of 1kg rests on a horizontal table. It is connected by a taut, light, inextensible string passing over a smooth fixed pulley, at the edge of the table, to another mass of 3kg hanging vertically. The 3kg mass it at a height of 0.5 metres above an inelastic floor when the system is released...
No of HLs = 3.7313432835820895522388059701493
No of HLs Activity %
0 131 100
1 65.5 50
2 32.75 25
3 16.375 12.5
4 8.1875 6.25
So its somewhere between 12.5% and 6.25%... Cant quite remember how to do it exactly.
My guess would be from 3...
KE = 1/2mv^2
PE = mgh
Work done = change in energy = force x displacement
Power = rate of doing work = force x velocity
F = ma
It has something to do with the above formulae, but no matter how i use them I can't get the right answer.
1. Find the power required to raise water 3m vertically from a tank and discharge it through a nozzle of cross-sectional area 0.0003m^2 at a speed of 10m/s.
2. A mass of 1kg rests on a horizontal table. It is connected by a taut, light, inextensible string passing over a smooth fixed pulley...