Recent content by Batman121

50-50 chance so ill go with yes i will need to add it. Thanks so much for your help :>

ok so now using W^2 and not multipling the mass by g i should getthe maximum reaction from the track. 500N X 10M X 0.9904^2 = 4904.46N and would i add gravity to find the max or not?

a mass in KG must be multiplied by gravity to get it into netwons M = 500 X 9.81 = 4905N R=10m W= v/r W=9.904 / 10 = 0.9904 m/s 4905 X 0.9904 X 10 = 48579.12N => 48.579KN ?

M=500kg = 500X10^3 W=9.904m/s ^2=98.0892 r= 10m (500x10^3) X (98.0892) X (10) = 490446080 In ENG form = 490.44608 X10^6 N 490.44MN the gavity also acting on it would be 9.81 X mass =...

so it would be mass of 500 X acceleration to get centrigufal force. but i don't know acceleration or how to work it out.

the only one i can think of is centripetal force + gravity has to equal the centrifugal force acting on the cars

The cars on a theme park ride each have a mass of 500 kg and travel around a vertical loop of diameter 20m. What is the minimum speed at which the cars must enter the loop in order to remain in contact with the track and What will then be the maximum reaction of the track? M=mass g=gravity...