Recent content by battery88

Yeah, that's definitely true. When you don't know the how and why it's hard to figure out which formulas to use in the first place.

Homework Statement Three people write programs. The following table shows the percentage of codes written by each person (A, B, C) and the percentage of buggy codes for each person. ****************Coder**************** *************A*B*C******************* Percent of code 30 25 45 Percent of...

Thanks for all your help. We're working on these more in class this week so it'll be nice to know what's going on.

So, would the answer be 27/64 * 1/3?

1/3.

Let me try again. the probability of getting a tail and two heads in any order = 3 * 3/4 * 3/4 * 1/4 = 27/64. And, the probability of getting THH out of {THH, HTH, HHT} = 1 * 3/4 * 3/4 * 1/4 = 9/64. So, 27/64 * 9/64 = .059

But, I'm not accounting for the bias.

Okay, the probability of getting a tail and two heads in any order = 3/8. And, the probability of getting THH out of {THH, HTH, HHT} = 1/3. So, 3/8 * 1/3 = 1/8

1/4 * 3/4 * 3/4 = 9/64

Multiply them.

Isn't there only one way to get THH, since it says "a tail followed by two heads on three flips"

Okay, thanks for the help. I've been stuck on this for hours.

Homework Statement Suppose we have a biased coin for which the probability of heads is 3/4 while the probability of tails is 1/4 . What is the probability of a tail followed by 2 heads on three flips of the coin? Homework Equations The Attempt at a Solution Here is what I have...

No, it doesn't since each toss is independent. So, it would be calculated the same way?

Homework Statement A coin is biased so that the probability of heads is 2/3. What is the probability that exactly four heads come up when the coin is flipped seven times, assuming that the flips are independent? Homework Equations The Attempt at a Solution C(7,4)(2/3)^4(1/3)^3 =...